For the open loop transfer function, G(s)H(s):

We have n=3 poles at s = 0,
-3, -2. We have m=0 finite zeros. So there exists q=3 zeros as s goes
to infinity (q = n-m = 3-0 = 3).

We can rewrite the open loop transfer function
as G(s)H(s)=N(s)/D(s) where N(s) is the numerator polynomial, and D(s) is the denominator
polynomial.

N(s)= 1, and D(s)= s^{3} + 5 s^{2} + 6 s.

Characteristic Equation is 1+KG(s)H(s)=0, or 1+KN(s)/D(s)=0,

or D(s)+KN(s)
= s^{3} + 5 s^{2} + 6 s+ K( 1 ) = 0

As you can see, the locus is symmetric about the real axis.

The open loop transfer function, G(s)H(s), has 3 poles, therefore the locus has
3 branches. Each branch is displayed in a different color.

Root locus starts (K=0) at poles of open loop transfer function, G(s)H(s).
These are shown by an "x" on the diagram above

As K→∞ the location of closed
loop poles move to the zeros of the open loop transfer function, G(s)H(s).
Don't forget we have we also have q=n-m=3 zeros at infinity. (We have
n=3 finite poles, and m=0 finite zeros).

The root locus exists on real axis to left of an odd number of poles and zeros
of open loop transfer function, G(s)H(s), that are on the real axis.
These real pole and zero locations are highlighted on diagram, along with the portion
of the locus that exists on the real axis.

Root locus exists on real axis
between:

0 and -2

-3 and negative infinity

... because on the real
axis, we have 3 poles at s = -2, -3, 0, and we have no zeros.

In the open loop transfer function, G(s)H(s), we have n=3 finite poles, and m=0
finite zeros, therefore we have q=n-m=3 zeros at infinity.

Angle of asymptotes
at odd multiples of ±180°/q, (i.e., ±60°, ±180°)

There exists 3 poles
at s = 0, -3, -2, ...so sum of poles=-5.

There exists 0 zeros, ...so sum of zeros=0.

(Any imaginary components of poles and zeros cancel when summed because they appear
as complex conjugate pairs.)

Intersect of asymptotes is at ((sum of poles)-(sum
of zeros))/q = -1.67.

Intersect is at ((-5)-(0))/3 = -5/3 = -1.67 (highlighted
by five pointed star).

Break Out (or Break In) points occur where N(s)D'(s)-N'(s)D(s)=0, or

3 s^{2}
+ 10 s + 6 = 0. (details below*)

This polynomial has 2 roots at s = -2.5,
-0.78.

From these 2 roots, there exists 2 real roots at s = -2.5, -0.78.
These are highlighted on the diagram above (with squares or diamonds.)

Not
all of these roots are on the locus. Of these 2 real roots, there exists 1 root
at s = -0.78 on the locus (i.e., K>0). Break-away (or break-in) points
on the locus are shown by squares.

(Real break-away (or break-in) with K
less than 0 are shown with diamonds).

* N(s) and D(s) are numerator and denominator
polylnomials of G(s)H(s), and the tick mark, ', denotes differentiation.

N(s)
= 1

N'(s) = 0

D(s)= s^{3} + 5 s^{2} + 6 s

D'(s)= 3 s^{2}
+ 10 s + 6

N(s)D'(s)= 3 s^{2} + 10 s + 6

N'(s)D(s)= 0

N(s)D'(s)-N'(s)D(s)=
3 s^{2} + 10 s + 6

Here we used N(s)D'(s)-N'(s)D(s)=0, but we could
multiply by -1 and use N'(s)D(s)-N(s)D'(s)=0.

No complex poles in loop gain, so no angles of departure.

No complex zeros in loop gain, so no angles of arrival.

Locus crosses imaginary axis at 2 values of K. These values are normally
determined by using Routh's method. This program does it numerically,
and so is only an estimate.

Locus crosses where K = 0, 30.2, corresponding
to crossing imaginary axis at s=0, ±2.45j, respectively.

These crossings
are shown on plot.

Characteristic Equation is 1+KG(s)H(s)=0, or 1+KN(s)/D(s)=0,

or D(s)+KN(s)
= s^{3} + 5 s^{2} + 6 s+ K( 1 ) = 0

So, by choosing K we
determine the characteristic equation whose roots are the closed loop poles.

For example with K=4.00188, then the characteristic equation is

D(s)+KN(s)
= s^{3} + 5 s^{2} + 6 s + 4.0019( 1 ) = 0, or

s^{3} +
5 s^{2} + 6 s + 4.0019= 0

This equation has 3 roots at s = -3.7,
-0.67 ± 0.8j. These are shown by the large dots on the root locus plot

Characteristic Equation is 1+KG(s)H(s)=0, or 1+KN(s)/D(s)=0, or

K = -D(s)/N(s)
= -( s^{3} + 5 s^{2} + 6 s ) / ( 1 )

We can pick a value of s
on the locus, and find K=-D(s)/N(s).

For example if we choose s= -0.7 + 0.84j
(marked by asterisk),

then D(s)=-4.15 + -0.222j, N(s)= 1 + 0j,

and K=-D(s)/N(s)=
4.15 + 0.222j.

This s value is not exactly on the locus, so K is complex,

(see note below), pick real part of K ( 4.15)

For this K there exist 3 closed
loop poles at s = -3.7, -0.66 ±0.83j.

Note: it is often difficult to choose
a value of s that is precisely on the locus, but we can pick a point that is close.
If the value is not exactly on the locus, then the calculated value of K will be
complex instead of real. Just ignore the imaginary part. These poles
are highlighted on the diagram with dots, the value of "s" that was originally specified
is shown by an asterisk.

Note: it is often difficult to choose a value of
s that is precisely on the locus, but we can pick a point that is close.
If the value is not exactly on the locus, then the calculated value of K will be
complex instead of real. Just ignore the the imaginary part of K (which will be
small).

Note also that only one pole location was chosen and this determines
the value of K. If the system has more than one closed loop pole, the location of
the other poles are determine solely by K, and may be in undesirable locations.